Question

an object is placed 10cm from a concave mirror of radius of curvature of 15cm. calculate the position nature and magnification of the image formed.
​

Answer 1

Step-by-step explanation:

$u = - 10cm$

$r = - 15cm$

$f = - \frac{15}{2} cm$

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$

$v = \frac{ - 150}{ (- 20 + 15)}$

$v = \frac{ - 150}{ (- 20 + 15)} = - 30cm$

$m = \frac{ - v}{u} = \frac{ - 30}{10} = - 3 \\ \\ thankyou \\ \\ hope \: it \: helps$