Question

an object is placed 13cm away from a concave lens of focal length 15cm .find the position, size and nature of the image​

Answer 1

* The image formed real

* The image formed is inverted

Answer 2

Explanation:

$\huge\underline{\underline{\ Question}}$

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An object is placed 13cm away from a concave lens of focal length 15cm .find the position, size and nature of the image

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$\huge\underline{\underline{\ Answer}}$

u = distance of object = - 13 cm

f = focal length = - 15 cm

By using lens formula...

$\implies \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \\ \implies \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \\ \implies \frac{1}{v} = \frac{1}{15} - ( - \frac{1}{13} ) \\ \implies {v} = 6.96cm$

$\\ \implies magnification = \frac{ - v}{u} \\ \implies m = \frac{ \cancel {- 6.96}}{ \cancel{- 15}} \\ \implies m = 0.464$

So, image is diminished real and inverted (as magnification is +ve)