an object is placed 15 centimetre from convex mirror of radius of curvature 90 cm calculate position of image and and magnification
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object distance(u) = -15cm
focal length (f)=90/2=45cm
then image distance (v)=?
1/v+1/u=1/f
=>1/v-1/15=1/45
=>1/v=1/45+1/15=4/45
=>v=45/4=11.25cm
magnification =(-v/u)=(-11.25/-15)=3/4=0.75
hence the image will be produced 11.25cm from the mirror towards right
hope this will help you my friend
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focal length (f)=90/2=45cm
then image distance (v)=?
1/v+1/u=1/f
=>1/v-1/15=1/45
=>1/v=1/45+1/15=4/45
=>v=45/4=11.25cm
magnification =(-v/u)=(-11.25/-15)=3/4=0.75
hence the image will be produced 11.25cm from the mirror towards right
hope this will help you my friend
you may follow me and mark as brainliest to get your answer thoroughly
parveshyadavbhai:
Very thanks full to you
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