Question

An object is placed 15 CM from a concave mirror who radius of curvature is 60cm find the position of image and magnification ​

Answer 1

Answer:

Hey mate!

Here's your answer!!

Focal length,

f=Radius of curvature /2=60/2=+30 cm

Object distance,

u=-15 cm

Using mirror formula

1/v + 1/u = 1/f

or 1/v=1/f- 1/u

1/v=1/30-(-1/15)

Image distance, v=10 cm

Now, magnification m=-v/u

m=-(10/(-15)=10/15=0.67

Hope it helps you!

plz mark if possible as brainliest

Explanation:

Answer 2

Explanation:

Given, u = -15cm and R = -60cm

we know that

focal length f = R/2 = -60/2 = -30cm

Now,

according to mirror formula

➡ 1/v + 1/u = 1/f

=> 1/v = 1/f - 1/u

=> 1/v = -1/30 + 1/15

=> 1/v = -1+2 /30

=> 1/v = 1/30

=> v = 30 cm

therefore , image is 30cm from the mirror and + sign show that image is virtual and erect .

Now,

➡ Magnification m = -v/u

=> m = -30/-15

=> m = 2

Hence, magnification of m is 2