Question

an object is placed 15 cm from a converging ( concave ) mirror that has a focal length of 10 cm
a. determine the image located
b. determine the magnification factor
c. if the object is 5 cm high how high is the image
d. what are the four characteristics of the image
plz try to answer faster

Answer 1

★ Ello ★

here is your answer !!


u = -15 cm


f = -10 cm.



v = ??


using the mirror formula we have


1 / u + 1 / v = 1 / f


= > 1 / -15 +1 / v = 1 / -10



=> 1 / v = 1 / -10 + 1 / 15

= > a =>>> v = -30 .


now ,

=>>>> B



magnification =>. - v / u

=>. -30 / 15

=> - 2


D ))) hence , the magnification is negative then we know that image is :-


real and inverted




C )))





height of image => ??





height of object = 5cm



magnification = image hight / object height



=> -2 = image distance / 5


hence , image distance is => 10 cm





$thanks$

Answer 2

Answer:

As It is of the concave mirror than the object distance and focal length is negative..

(a)

u = -15

f = -10

v = ?

By The Formula!!

1/v + 1/u = 1/f

1/v + 1/-15 = 1/-10

1/v = 1/-10 - 1/-15

1/v = 1/-10 + 1/15

1/v = (-3 + 2)/30

1/v = -1/30cm

or

v = -30cm...

(b)

magnification = -(image distance)/(object distance)

or

m= -v/u

m = -(-30)/-15

m = 30/-15

m = -2 cm

(c)

ht. of object = 5cm

ht. of image = ?

magnification = -2cm

m=hi/ho

-2 = hi/5

hi = -10 cm

Explanation:

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