Question

An object is placed 15 cm from a convex mirror of focal length 10cm . Calculate the image distance and magnification produced​

Answer 1

Explanation:

Mirror...... =___=

1/f = 1/v +1/u

1/10 = 1/v -1/15.......................

(focal length of convex is +ve)

1/v = 1/10 + 1/15

1/v = 5/30

1/v = 1/6

v = 6

From this we come to know image is erect and virtual

M = -v/u

= -6/-15

= 6/15

= 2/5

M = 0.4

(this shows image has now became small as compared to original)

Answer 2

Answer:

6 cm  and 0.5 respectively .

Explanation:

Given :

Object distance ( u ) = 15 cm

Focal length ( f ) = 10 cm

We have to find  image distance and magnification produced​ .

1.

Using mirror formula

1 / f = 1 / u + 1  / v

1 / v = 1 / f + 1 / u   [ used sign convention ]

Putting values now :

1 / v = 1 / 15 + 1 / 10

1 / v = 5 / 30

1 / v = 1 / 6

v  = 6 cm .

Thus the image distance is 6 cm .

2.

m = - ( v / - u )

m =  6 / 15

m = 2 / 5

m = 0.4

Hence we get both answer .