Question

An object is placed 15cm in front of a convex lens of focal length 10cm . Where should a concave mirror of radius of curvature 20 cm be placed so that the final image is formed at the position of the object itself?
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Answer 1

Step-by-step explanation:

1+u1=f1

v1−101=151

v1=151+101=15025

v=6cm

Hence image will be formed 6 cm beyond the mirror, i.e virtual magnification

m=u−v=−10−6=0.6

Hence it will be erect and diminished.