Question

An object is placed 16.0 cm in front of a concave mirror of focal length 14.0 cm. The mirror forms a real
and inverted image of height 17.5 cm.
What is the height of the object, how?​

Answer 1

Hello Mate! Here is your answer:

Given,

Object Distance (u) = 16 cm (negative)

Focal Length (f) = 14 cm (negative)

[These values are negative because of the conventional sign rule of Concave mirror]

Image height (h2) = 17.5 cm

Let the Image Distance be denoted as 'v',

1/f = 1/v+1/u

-1/14 = 1/v-1/16

-1/14+1/16 = 1/v

(-8+7)/112 = 1/v

-1/112 = 1/v

-112 cm = v

Linear Magnification (m) = -(v/u)

= -(-112/-16)

= -7

Let the Object height be h1,

h2 = m*h1

17.5 = 7h1

2.5 cm = h1

The Height of Object is 2.5 cm.

Linear Magnification tells us about how magnified the image is so using that relation, we found this value.

I hope this helps.

Answer 2

Explanation:

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