Question

An object is placed 20 cm in front of a convex mirror of radius of curvature 80 cm. The distance of the image formed by the mirror is ____ cm from its pole

Answer 1

Heya !!

Here's your answer.. ⬇⬇

Radius ( R ) = 80cm

Focal length ( f ) = R/2
= 80/2
= 40cm

Object Distance ( u ) = ( -20 )cm

Image Distance ( v ) = ? cm

Solve using Mirror Formula..

Mirror Formula :-

$\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\ \\ \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \\ \\ \frac{1}{v} = \frac{1}{40} - ( - \frac{1}{20}) \\ \\ \frac{1}{v} = \frac{1}{40} + \frac{1}{20} \\ \\ \frac{1}{v} = \frac{1}{40} + \frac{2}{40} \\ \\ \frac{1}{v} = \frac{1 + 2}{40} \\ \\ \frac{1}{v} = \frac{3}{40} \\ \\ v = \frac{40}{3}$
v = 13.33 cm


Image Distance is 13.33cm ( approx. )

Hope it helps

Thanks (: