Question

An object is placed 21 cm in front of a concave mirror of radius of curvature 10 cm. A
glass slab of thickness 3 cm and refractive index 1.5 is placed close to the mirror in the
space between the object and the mirror. Find the position of the final image formed. Take
the distance of the near surface of the slab from the mirror to be 1 cm. ​

Answer 1

Explanation:

The shift in position of object due to slab is given by 

 

Δt=t(1−μ1)=3(1−231)=3(1−32)=1cm

The apparent distance of object from mirror 21−1=20cm

The position of image formed by concave mirror can be found by mirror formula

v1+u1=f1...(i)

As object and focus of mirror lies left side of pole of mirror

u=−20,f=−2R=−5

substituting values in equation (i)

v1+−201=−51

v1=201−204

v=−320

As image is other side of the slab,the image will be again shifted by 1 cm away from mirror.

Final distance of image from

20/3+1cm=7.67 cm

Answer 2

Answer:

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