an object is placed 24 cm from a concave mirror its image is inverted and doubles the size of the object find the focal length of the mirror and the position where the image is formed
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u = -24
m = -2
m = -v/u
-2 = -v/u
v = -24×2
v = -48
Image of is -48
Formed in front of the mirror
1/f = 1/v + 1/u
1/f = 1/-48 + 1/-24
1/f = -1-2/48
1/f = -3/48
1/f = -1/16
f = -16
focal length of the mirror f = -16
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