An object is placed 50 cm from a lens produces a virtual image at a distance of 10cm in front of the lens. Draw a diagram show the formation of image. Calculate focal length of the lens and magnification produced
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Given :-
Distance of object from the mirror u=−50 cm
Distance of image from the mirror v=−10 cm
Solution :-
For lens, we know
1/f = 1/v - 1/u
☞ 1/f = 1/-10 - 1/-50
☞ f = - 12.5 cm
f = −12.5cm
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m = v / u
☞ m = - 10 / - 50
☞ m = + 1 / 5
☞ m = + 0.2
m = + 0.2
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