Question

an object is placed 50 cm infront of concave mirror of focal length 30 cm find the nature position of the image​

Answer 1

Answer:

$v = \frac{75}{4}$

Explanation:

Plz refer the image!!

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Answer 2

Answer:

Position of Image : 75 cm in-front of the mirror

Nature of Image : Real , Inverted and enlarged

Explanation:

object distance u = - 50 cm

focal length f = - 30 cm ( ∵ concave mirror)

From Mirror Formula :

$\frac{1}{v} +\frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} - \frac{1}{50} = - \frac{1}{30}$

$\frac{1}{v} = \frac{1}{50} - \frac{1}{30}$$\frac{1}{v} = - \frac{20}{1500} = - \frac{1}{75}$

∴ v = - 75 m

Image is formed at a distance of 75 cm in-front of the mirror.

magnification m = - v/u = - (-75)/(-50) = - 1.5

Since m is negative : Image is real and inverted

since |m| > 1 : Image is enlarged(magnified)