An object is placed 6cm in front of a convex lens of focal length 12 cm. Find the position, nature and magnification of the image
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u= -6cm
f= +12cm
1/f = 1/v - 1/u
1/f + 1/u = 1/v
1/12 -1/6 =1/v
1-2/12 =1/v
v = -12cm
m= v/u
=-12/-6
=+2
nature of image is virtual and erect.
hope this will help you☺
f= +12cm
1/f = 1/v - 1/u
1/f + 1/u = 1/v
1/12 -1/6 =1/v
1-2/12 =1/v
v = -12cm
m= v/u
=-12/-6
=+2
nature of image is virtual and erect.
hope this will help you☺
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