Question

An object is placed 70cm from a converging lens of focal length 30cm. What is the nature and position of the image formed?​

Answer 1

Answer:

please refer the attachment

Explanation:

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Answer 2

Answer:

We can use Gaussian equation for thin lens with Cartesian sign convention . 1/f = 1/v - 1/ u

Here, object distance, u = -30 cm.

Focal length , f= 50 cm.

Image distance, v = ?

Thus, 1/50= 1/v -(-1/u) OR

1/50 - 1/30 = 1/v OR

v= - 75 cm.

Explanation: