An object is placed at 0.06 m from a convex lens of focal length 0.1 m, calculate the position of the image, nature and height of image if object is 5 cm high?
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u= -0.06m= 60cm, f= 0.10m = 10cm
​We know, 1/f= 1/v - 1/u
1/10 = 1/v - 1/60 = 1/v= 1/60 + 1/10 = 1+6/60 = 7/60
therefore, v= 70/6= 11.67 cm
thus, image is formed 11.67 cm behind the lens.
m= v/u= 11.67/-60= -0.19
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