an object is placed at 0.06m from a convex lens of focal length 10m. calculate the position nature of the image formed
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focal length = 10 m ( given)
u = -0.06m
v=?
using formula...
we have..
1/v+1/u=1/f
1/v+1/-0.06=1/10
1/v=1/10+1/0.06
v=100m
m=-v/u
=-(-100)/0.06
u = -0.06m
v=?
using formula...
we have..
1/v+1/u=1/f
1/v+1/-0.06=1/10
1/v=1/10+1/0.06
v=100m
m=-v/u
=-(-100)/0.06
jansiiii:
bhosdike 1/v -1/u hoga naan
ohh Jban sbhal ker
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