An object is placed at 10cm from a concave mirror produced 3 times magnified real image. calculate focal length of the mirror.
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Explanation:
Solution
As per the given conditions,
m = 3 {A concave mirror produces three times enlarged image of an object and the }
u = -10 cm
Formula
We know that,
m=−vu
Substituting the known values we get,
3 = (-v)/(-10)
v = 30
The distance between the mirror and image = 30 cm
From mirror formula, we know
1v+1u=1f
⇒ 130+1−10=1f
(-2)/30 = 1/f
or f = – 15
The radius of curvature R = 2f
∴ R = 2 × (- 15)
R = -30 cm
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