An object is placed at 15 cm from a concave mirror of radius of curvature 60 cm find the position and its magnification
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u= -15cm
r=60cm
r=2f =>f=r/2 => f= 30cm
1/v - 1/u= 1/f
!/v - (1/-15)= 1/30 => 1/v= 1/30+1/15 => !/v= 1+2/30
1/v=3/30 => 1/v=1/10
v=10
m= -v/u
= -10/-15= 2/5=0.4
r=60cm
r=2f =>f=r/2 => f= 30cm
1/v - 1/u= 1/f
!/v - (1/-15)= 1/30 => 1/v= 1/30+1/15 => !/v= 1+2/30
1/v=3/30 => 1/v=1/10
v=10
m= -v/u
= -10/-15= 2/5=0.4
arunkumartiwari:
How did1+2/30 come?
Answered by
0
Answer:
Explanation:u= -15cm
r=60cm
r=2f =>f=r/2 => f= 30cm
1/v - 1/u= 1/f
!/v - (1/-15)= 1/30 => 1/v= 1/30+1/15 => !/v= 1+2/30
1/v=3/30 => 1/v=1/10
v=10
m= -v/u
= -10/-15= 2/5=0.4
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