Physics, asked by arunkumartiwari, 1 year ago

An object is placed at 15 cm from a concave mirror of radius of curvature 60 cm find the position and its magnification

Answers

Answered by amitrawar1947
0
u= -15cm

r=60cm

​r=2f =>f=r/2 => f= 30cm

​1/v - 1/u= 1/f

!/v - (1/-15)= 1/30 => 1/v= 1/30+1/15 => !/v= 1+2/30

1/v=3/30 => 1/v=1/10

v=10

m= -v/u

= -10/-15= 2/5=0.4

arunkumartiwari: How did1+2/30 come?
arunkumartiwari: And.is 2
Answered by manvikirohi2tech
0

Answer:

Explanation:u= -15cm

r=60cm

​r=2f =>f=r/2 => f= 30cm

​1/v - 1/u= 1/f

!/v - (1/-15)= 1/30 => 1/v= 1/30+1/15 => !/v= 1+2/30

1/v=3/30 => 1/v=1/10

v=10

m= -v/u

= -10/-15= 2/5=0.4

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