An object is placed at 15 cm from a concave mirror of radius of curvature 60 cm find the position and its magnification
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Given, u = -15cm and R = -60cm
we know that
focal length f = R/2 = -60/2 = -30cm
Now,
according to mirror formula
➡ 1/v + 1/u = 1/f
=> 1/v = 1/f - 1/u
=> 1/v = -1/30 + 1/15
=> 1/v = -1+2 /30
=> 1/v = 1/30
=> v = 30 cm
therefore , image is 30cm from the mirror and + sign show that image is virtual and erect .
Now,
➡ Magnification m = -v/u
=> m = -30/-15
=> m = 2
Hence, magnification of m is 2
【 Hope it helps you 】
Given, u = -15cm and R = -60cm
we know that
focal length f = R/2 = -60/2 = -30cm
Now,
according to mirror formula
➡ 1/v + 1/u = 1/f
=> 1/v = 1/f - 1/u
=> 1/v = -1/30 + 1/15
=> 1/v = -1+2 /30
=> 1/v = 1/30
=> v = 30 cm
therefore , image is 30cm from the mirror and + sign show that image is virtual and erect .
Now,
➡ Magnification m = -v/u
=> m = -30/-15
=> m = 2
Hence, magnification of m is 2
【 Hope it helps you 】
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