Question

an object is placed at 15 cm from a convex mirror having the radius of curvature 20cm find the position and kids and kids of image formed by it​

Answer 1

$f = \frac{r}{2}$

f=+10cm

Using mirror equation:

$\frac{1}{10} = - \frac{1}{15 } + \frac{1}{v}$

$\frac{1}{v} = \frac{1}{10} + \frac{1}{15}$

$\frac{1}{v} = \frac{3 + 2}{30}$

$\frac{1}{v} = \frac{5}{30}$

v=+6cm virtual &erect

Answer 2

Given that,

Object distance, u = -15 cm

Radius of curvature of convex mirror, R = 20 cm

So, focal length, f = +10 cm

To find,

The position and kind of image formed.

Solution,

Using mirror's formula to find it as :

$\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{(10)}-\dfrac{1}{(-15)}\\\\v=6\ cm$

The image will form at a distance of 30 cm. Magnification is given by :

$m=\dfrac{-v}{u}\\\\m=\dfrac{-6}{-15}\\\\m=0.4$

The formed image is virtual and erect.

Learn more,

Mirror's formula

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