An object is placed at 15 CM in front of a concave mirror. If the magnification of the image formed is (-2) then determine the image distance and focal length of the mirror.
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Explanation:
Here, object distance= u = -15 cm.
Image distance= v
Focal length=f =-20 cm (concave mirror)
Now, (1/v) + (1/u) = (1/f)
=> (1/v) = (1/f) - (1/u)
=> (1/v)= (-1/20)- (-1/15)
=> (1/v)= (1/60)
=> v = 60 cm
Since (v) is positive , image is formed behind the mirror.
==>Therefore the image is virtual and upright.
Magnification = m = (-v/u) = 4.
Thus, the image has a height 4 times that of the object.
=> Height of image = 4*(height of object)= 4*4 = 16 cm
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