Question

an object is placed at 20 centimetre in front of a convex mirror of focal length 10 cm calculate the position of the image
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Answer 1

Answer:-

v = 6.66 cm

Given :-

u = - 20 cm

f = 10 cm

To find :-

The position of the image formed.

Solution:-

By using mirror formula,

$\huge \boxed {\dfrac{1}{f} = \dfrac{1}{v}+\dfrac{1}{u}}$

Put the given value,

→$\dfrac{1}{10}= \dfrac{1}{v}-\dfrac{1}{20}$[/tex]

→$\dfrac{1}{v}= \dfrac{1}{10}+\dfrac{1}{20}$

→$\dfrac{1}{v} = \dfrac{2 + 1}{20}$

→$\dfrac{1}{v} = \dfrac{3}{20}$

→$v = \dfrac{20}{3}$

→$v = 6.66 cm$

hence,

The image formed at a distance of 6.66 cm.

Answer 2

Answer :-

Object will be placed on the right side and would be at 6.66cm away from pole

Explanation :-

We, have formula

$\mathsf{\huge{\underline{\boxed{1/f=1/v+1/u}}}}$

Where,

R = radius of curvature

f = focal length

Given :-

Focal length = 10 cm

v (image distance) = ?

u (object distance) = -20 ( In mirror u is always -ve)

Solution :-

Put value in formula, we have

1/10 = 1/v - 1/(-20)

So,

» 1/v = 1/10 + 1/20

by taking L.C.M

» 1/v = 2+1/20

» 1/v = 3/20

Now, by doing reciprocal

» v = 20/3

v = 6.66 cm

Hence the image is formed at a distance of 6.66cm