Question

An object is placed at 36.0 cm in front of a concave mirror of focal length 12.0 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image?What is the nature of the image?​

Answer 1

U=36

v=?

F= 12

Answer:

1/v+1/U=1/F

now, putting the given value value in formula

1/V+1/36=1/12

1/V=1/12-1/36

1/V=1/36

cross multiplying

V=36cm

V=U

so,

object is placed on center of curvature

the nature of image will be real, inverted....

HOPE YOU WILL UNDERSTAND ....