Question

An object is placed at 4 cm distance in front of a
concave mirror of radius of curvature 24 cm. Find
the position of image. Is the image magnified ?
Ans. 6 cm behind the mirror, Yes​

Answer 1

Answer:

Image distance, v = 6 cm. It is 1.5 times magnified.

Explanation:

given,

Object distance, u = -4 cm

Radius of curvature, R = 24 cm

Focal length, f = -12 cm

Using mirror's equation :

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{-12}-\dfrac{1}{-4}$

v = 6 cm

The image is formed at a distance of 3 cm in front of mirror.

The magnification of the mirror is given by :

$m=\dfrac{-v}{u}$

$m=\dfrac{-6}{-4}$

m = 1.5

The image is 1.5 times magnified.