Question

an object is placed at 40 cm in front of a convex mirror at radius of curvature of 20cm. find the position ,nature, and magnification of the image formed by the mirror

Answer 1

Answer:

1/f=(1/v)-(1/u)

f=(u-v)/uv

-40=(-40-v)/-40v

-40=(40+v)/40v

-40×40v=40+v

-1600v=40+v

-1601v=40

v=40/-1601

v=-0.02