An object is placed at 45 cm in front of converging mirror ( CONVEX MIRROR ) of radius of curvation 30cm. At what distance the image would be formed. Mention the nature of the image ( BY EXPLANATION )
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Answer:
Given,
Type of Spherical Mirror = Convex
Object Distance (u) = -45 cm
[Value taken as negative because object is placed on opposite side of shiny part of convex mirror]
Radius of Curvature (R) = +30 cm
Focal Length (f) = R/2
= +30/2 cm
= +15 cm
Let's take image distance as v cm.
According to equation,
= 1/f = 1/v+1/u
= 1/15 = 1/v - 1/45
= 1/15 + 1/45 = 1/v
= ( 3 + 1 )/45 = 1/v
= 4/45 = 1/v
= 45/4 cm = v
= 11.25 cm = v
The Image is formed at 11.25 cm away from the pole of the mirror.
The Image is virtual as the light rays appear to meet in a convex mirror.
The Image is diminished in size like it is in a convex mirror.
I hope this helps.
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