An object is placed at 5 cm in front of a concave mirror of radius of curvature 15 cm. Find the position, nature, and magnification of the image in each case.
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Answer:
position of image = -3cm
magnification = -0.6
nature : real and inverted
Explanation:
u = -5cm
f = -7.5
1/f = 1/v + 1/u
v = -3cm[by solving with formula]
m = -v/u
= -(3/5) = -0.6
position of image = -3cm
magnification = -0.6
nature : real and inverted
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