Question

An object is placed at 5 cm infront of a concave
mirror of radius of curvature 15 cm. The
position of image (v) and its magnification (m)
are
1) v= 15 cm; m=3 (virtual, erect)
2)v=5 cm; same size (virtual, erect)
3)v=5 cm; same size (real, inverted)
4) v= 15 cm; m=3 (real, inverted)​

Answer 1

Explanation:

as object is before focus its image will be real nd inverted