Question

An object is placed at 6 cm distance in front of a concave mirror of focal length 4cm.
Find the position of the image and
What will be the nature of the image?​

Answer 1

Answer:

-1/f =1/-v 1/-u =- 1/4=1/-v+1//-6= v=-2.4

Explanation:

so concave lens all will be minus sines.so here v is minus sine.its nature will be virtual, erect ,magnified.

Answer 2

Given, object distance, u = -6 cm

focal length, f = -4 cm

according to mirror formula...

1/f = 1/v + 1/u

-1/4 = 1/v - 1/6

1/v = 1/6 - 1/4

1/v = -2/24

v = -12 cm

Negative sign shows that the image is real and inverted..It is formed at 12 cm before the mirror

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