Question

An object is placed at 60 m in front of a concave mirror if its radius of curvature is 40 m then find the image distance

Answer 1

*Given:

Object distance=p=50cm

Radius of curvature=R=60cm

then f=R/2

f=60/2

f=30cm

image distance=q=?

using mirror formula

1/f=1/p+1/q

1/30=1/50+1/q

1/30–1/50=1/q

(5–3)/150=1/q

2/150=1/q

2q=150

q=75

Image distance=75cm

Answer 2

Answer:

${\fbox{\boxed {\huge{\rm{\pink{Answer!!}}}}}}$

Explanation:

Object distance => p = 60m

Radius of the curvature =>R=40m

${\rm{then \: f = \frac{R}{2}}} \\ {\implies{\rm{f =\frac{40}{2}}}} \\ {\boxed{\implies {\rm{f = 20m}}}}$

Image distance =>q=?

Using mirror formula

${\boxed{\implies{\rm{ \frac{1}{f} = \frac{1}{p}+ \frac{1}{q}}}}}$

${\implies{\rm{\frac{1}{20} = \frac{1}{60} + \frac{1}{q}}}} \\ {\implies{\rm {\frac{1}{20} - \frac{1}{60} = \frac{1}{q}}}} \\ {\implies{\rm{ \frac{3 - 1}{60} = \frac{1}{q} }}} \\ {\implies{\rm{ \frac{2}{60} = \frac{1}{q}}}} \\ {\implies{\rm{2q = 60}}} \\ {\fbox{\boxed{\implies {\rm{q = 30m}}}}}$

Image Distance =30m

${\blue\rm{bebrainly}}}$