Question

an object is placed at 8cm from a concave lens of focal length 24cm where is the image formed and what is its magnification​

Answer 1

Answer:

image = -6cm

magnificent = - 0.75

Explanation:

u = -8

f = -24

1/f = 1/v - 1/u

1/v = 1/f + 1/u

1/v = 1/-24 + 1/-8

1/v = -8 -24/192

v = -192/32

v = -6

m= -v/u

m = - (-6)/-8

m = -3/4

m = -0.75