An object is placed at a distance 30 cm from a concave lens of focal length 30
cm
i) Use lens formula to determine the distance of the image from
the lens.
ii) List four characteristics of the image ( nature, position, size,
erect/ inverted) in this case.
iii) Draw a labelled diagram to justify your answer of part (ii)
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concave lens produces a virtual, erect diminished image.
concave lens produces a virtual, erect diminished image.Using Real Is Positive RIP Convention, u=30 and f=-15
concave lens produces a virtual, erect diminished image.Using Real Is Positive RIP Convention, u=30 and f=-151/u+1/v=1/f
concave lens produces a virtual, erect diminished image.Using Real Is Positive RIP Convention, u=30 and f=-151/u+1/v=1/f1/30+1/v=−1/30
1/v=−1/30−1/30=−3/30=−1/10
−1/30=−3/30=−1/10v=−10M=v/u=−1/3
−1/30=−3/30=−1/10v=−10M=v/u=−1/3So image is erect, virtual, 1/3 size of object, and 10 cm from the lens, (between lens and object)
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