Question

an object is placed at a distance od 10cm from m the concave lens of focal lenght of 20cm. fibd the position of image. jai hc verma ​

Answer 1

Step-by-step explanation:

OBJECT DISTANCE = -10 CM

FOCAL LENGTH = -20 CM.

BY LENS FORMULA

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} - \frac{1}{ - 10} = \frac{1}{ - 20} \\ \\ \frac{1}{v} + \frac{1}{10} = \frac{1}{ - 20} \\ \\ \frac{1}{v} = \frac{1}{ - 20} - \frac{1}{10} \\ \\ \frac{1}{v} = \frac{1}{20} \\ v = 20cm$