Question

an object is placed at a distance of 10 centimetres from a convex mirror of focal length 5 cm 1) draw a ray diagram showing the formation of image 2) state two characteristics of image formed 3) calculate the distance of the image from mirror

Answer 1

(a) Refers to the attachment for this answer.

(b)  Focal length(f) of the lens is less than the object distance(u). This means that the Object is kept behind the Focus.
 For Convex Mirror, we know that the Characteristics of the Image which is formed when the object is kept between Infinity and Focus are Virtual, Erect, and Diminished at the Point.

(c) Given conditions ⇒
Object Distance(u) = 10 cm. (negative)
Focal length of the lens (f) = 5 cm.

We know, convex mirror always forms the virtual, upright and diminished.Also, Object distance in the convex mirror is always negative where as Image distance and focal length are positive.

Now, Applying the Mirror's Formula,

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$
⇒ $\frac{1}{5} = \frac{1}{v} + \frac{1}{-10}$
⇒  1/5 = (10 - v)/10v
⇒ 10v = 50 - 5v
⇒ 15v = 50
⇒ v = 50/15
∴ v = 10/3 
∴ Image Distance(v) = 3.33 cm.


Hence, the Image is formed on the other side of the Mirror at the distance of 3.33 cm.


Hope it helps.

Answer 2

Answer:

3.33cm.

Explanation:

1/f=1/v+1/u

1/5=1/v+1/-10

1/5=(10-v)/10v

10v=50-5v

15v=50

v=50/15

v =10/3

Image distance (v) = 3.33 cm.

Hope it helps you

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