An object is placed at a distance
of 10 cm from a Concave mirror of focal length 15 cm. Find the position and nature of the image.
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U = -10 cm
F = -15 cm
1/f = 1/v - 1/u
1/-15 = 1/v - 1/-10
-1/v = 1/15 + 1/10
-1/v = 2+3/30
-1/v = 1/6
v = -6 cm
Nature of Image-
Enlarged
Virtual and Erect
Behind the Mirror
Answered by
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✰ Question Given :
- An object is placed at a distance of 10 cm from a Concave mirror of focal length 15 cm. Find the position and nature of the image.
✰ Required Solution :
★ Value Given to us :
- object is placed at a distance of 10 cm
- Concave mirror of focal length 15 cm.
★ Formula Used Here :
- 1/v + 1/u = 1/f
★ Putting Value in Formula :
- ➦ 1/v + 1/(- 15) = 1/10
- ➦ 1/v - 1/15 = 1/10
- ➦ 1/v = 1/10 + 1/15
- ➦ 1/v = (3 + 2)/30
- ➦ 1/v = 5/30
- ➦ 1/v = 1/6
- ➦ v = 6 cm
★ Hence, the image distance is 6 cm. ★
✰ Nature , Position of the image :
- The image is formed behind the mirror and it is virtual and erect.
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