Question

An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.​

Answer 1

here is your answer

U= -10 cm

f= 15 cm

1/f = 1/v + 1/u

So, 1/v= 1/f - 1/u

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Therefore v=5/30 = 6 cm

Hence the image is formed behind the mirror and therefore it is virtual and erect

Answer 2

GIVEN:

Image distance (u)=-10 cm

focal length (f)=15 cm

SOLUTION:

1/f=1/v+1/u

1/v=1/f- 1/u

1/v=1/15-(- 1/10)

1/v=25/150

v=150/25

v=6 cm

object is formed behind the mirror

m= -v/u= -6/-10=0.6

the image formed is virtual erect and small

I hope this helps ( ╹▽╹ )