Question

an object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm find the magnification of the image
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Answer 1

Question :–

An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm find the magnification of the image.

Given :–

1. u = 10 cm
2. F = 15 cm

To Find :–

• The magnification of the image.

Formula Used :–

• $\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

Solution :–

We know that,

F & u are given above in the question already.

So, We will find v.

So, the formula will be :-

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

$\frac{1}{v} = \frac{1}{15} - \frac{1}{10}$

【L.C.M. is refer in the above attachment】

$\frac{1}{v} = \frac{2 + 3}{30}$

$v = \frac{ \cancel5}{ \cancel30}$

$v = 6 \: cm$

Hence, the image is formed as virtual magnification.

$m = \frac{ - v}{ - u}$

$m = \frac{ - 6}{ - 10}$

$m = 0.6$

Hence, it will be diminished & erect.