Question

An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. find
the position and nature of the image.​

Answer 1

Explanation:

It is to be remembered that a convex mirror always forms the virtual, erect and diminished image.

Given: Object distance, u=−10cm     Focal length, f=15cm

To find: Image distance, v

From mirror formula :

v1+u1=f1

v1−101=151

v1=151+101=15025

v=6cm

Hence image will be formed 6 cm beyond the mirror, i.e virtual magnification

m=u−v=−10−6=0.6

Hence it will be erect and diminished.

Answer 2

$\huge\overbrace{\underbrace\blue{Answer}}$

GIVEN:

Image distance (u)=-10 cm

focal length (f)=15 cm

SOLUTION:

1/f=1/v+1/u

1/v=1/f- 1/u

1/v=1/15-(- 1/10)

1/v=25/150

v=150/25

v=6 cm

object is formed behind the mirror

m= -v/u= -6/-10=0.6

the image formed is virtual erect and small