An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm.
Find the position and nature of the image formed.
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Explanation:
It is to be remembered that a convex mirror always forms the virtual, erect and diminished image.
Given: Object distance, u=−10cm Focal length, f=15cm
To find: Image distance, v
From mirror formula :
v1+u1=f1
v1−101=151
v1=151+101=15025
v=6cm
Hence image will be formed 6 cm beyond the mirror, i.e virtual magnification
m=u−v=−10−6=0.6
Hence it will be erect and diminis
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