Question

An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. find the position and nature of the image

Answer 1

image formed will be virtual and erect (object placed anywhere between pole and infinity)

image position +6cm
and magnification =0.6

Answer 2

According to the Question

U = -10cm

F = 15cm

Using mirror formula :-

$\bf\huge\frac{1}{V} + \frac{1}{U} = \frac{1}{F}$

$\bf\huge\frac{1}{V} + \frac{1}{-10} = \frac{1}{15}$

$\bf\huge\frac{1}{V} = \frac{1}{15} + \frac{1}{10}$

$\bf\huge\frac{1}{V} = \frac{5}{30}$

$\bf\huge v = \frac{30}{5}$

V = 6cm

Image will be formed at distance of 6cm

Image Nature = Virtual , Erect and Behind the mirror

Hence

Magnification

$\bf\huge m = - \frac{V}{U}$

$\bf\huge m = - \frac{6}{-10}$

m = 0.6

Image will be fomed 60% smaller than the object