an object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position of image
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Here’s the answer
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Given
Focal length ( f ) = 15 cm
Object distance ( u ) = - 10 cm
Image distance ( v ) = ?
We know
1/f = 1/u + 1/v
1/15 = 1/(-10) + 1/v
1/v = 1/10 + 1/15
1/v = ( 3 + 2 )/30
1/v = 5/30
1/v = 1/6
v = 6 cm
Hence image is virtual errect
Or is 6 cm at right of principal
HOPE HELPED
PEACE :)
Here’s the answer
————————————
Given
Focal length ( f ) = 15 cm
Object distance ( u ) = - 10 cm
Image distance ( v ) = ?
We know
1/f = 1/u + 1/v
1/15 = 1/(-10) + 1/v
1/v = 1/10 + 1/15
1/v = ( 3 + 2 )/30
1/v = 5/30
1/v = 1/6
v = 6 cm
Hence image is virtual errect
Or is 6 cm at right of principal
HOPE HELPED
PEACE :)
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