Question

an object is placed at a distance of 10 cm from the convex lens of focal length 12 cm what is the position and nature of the image​

Answer 1

Explanation:

u= 10cm

f= 12 cm

v= ?

=> 1/f = 1/u+1/v

=> 1/v = 1/f-1/u

= 1/12 - 1/10

= (5-6)/60

= -1/60

=>. v = -60 cm

since object is placed between focus and lens.

hence image is virtual , erect, longer in size

and same side of object at a distance 60cm

from the convex lens.

hope this helps you