Question

An object is placed at a distance of 10 cm on the principle axis of a convex lens whose focal length is less than 10 cm then the image of it observed at a distance of 30cm from the lens find the nature and magnification of image
​

Answer 1

Explanation:

nature virtual and erect

size larger than object

position beyond F on the same side

Answer 2

The image formed will be real, inverted and magnified. The image is formed at a point beyond 2f.

$M=3$ is the magnification factor of the lens.

Explanation:

Given:

distance of the object form the lens, $o=10\ cm=0.1\ m$

distance of the image form the lens, $i=30\ cm=0.3\ m$

Now using the lens formula:

$\frac{1}{f} =\frac{1}{i} +\frac{1}{o}$

$\frac{1}{f} =\frac{1}{0.3}+ \frac{1}{0.1}$

$f=0.075\ m=7.5\ cm$

• So, we observe that the object is placed between f and 2f of the lens.

So, the image formed will be real, inverted and magnified. The image is formed at a point beyond 2f.

Now the magnification of the image will be:

$M=\frac{i}{o}$

$M=\frac{30}{10}$

$M=3$ is the magnification factor

#learnmore

TOPIC: convex lens

https://brainly.in/question/11724847