Physics, asked by laxmishenoy498, 11 months ago

An object is placed at a distance of 10cm from a concave mirror of focal length 20cm

A. Calculate the image distance

Answers

Answered by Anonymous
13

\huge{\star}{\underline{\boxed{\red{\sf{Answer :}}}}}{\star}

Concave Mirror

Object distance (u) = -10 cm

Focal length (f) = -20 cm

==================

We have to find image distance (v)

Put value in formula :-

\huge{\boxed{\boxed{\tt{\frac{1}{f} \: = \: \frac{1}{v} \: + \: \frac{1}{u}}}}}

\LARGE{\sf{\frac{1}{v} \: = \: \frac{1}{f} \: - \: \frac{1}{u}}}

______________[Put Values]

\LARGE{\sf{\frac{1}{v} \: = \: \frac{1}{-20} \: - \: \frac{1}{-10}}}

\LARGE{\sf{\frac{1}{v} \: = \: \frac{1}{-20} \: + \: \frac{1}{10}}}

\LARGE{\sf{\frac{1}{v} \: = \: \frac{-1 \: + \: 2}{20}}}

\LARGE{\sf{\frac{1}{v} \: = \: \frac{1}{20}}}

\huge{\implies}{\boxed{\boxed{\red{\sf{v \: = \: 20 \: cm}}}}}

•°• Image distance is 20 cm

Answered by TheAstrophile
4

\mathfrak{Answer}

\mathcal{Given:}

Object distance, u = -10 cm

Focal length, f = -20 cm

\mathcal{Solution:}

 \frac{1}{v}  +  \frac{1}{u}  =  \frac{1}{f}

 \frac{1}{v}  =  \frac{1}{f}  -  \frac{1}{u}

 \frac{1}{v}  =  \frac{1}{ - 20}  -  \frac{1}{ - 10}

 \frac{1}{v}  =  -  \frac{1}{20}  +  \frac{1}{10}

  \frac{1}{v} =  \frac{ - 10 + 20}{200}

 \frac{1}{v}  =  \frac{10}{200}

 \frac{1}{v}  =  \frac{1}{20}

v = 20 \: cm

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