Physics, asked by snehahoty849, 5 months ago

An object is placed at a distance of 10cm from a concave mirror. A real, enlarged image is formed at a distance of 5cm from the object. Find the focal length of the mirror.
plz help me​

Answers

Answered by plaannet24
0

Answer:

Soln :-. Given u = -10cm , v= ? , f = -15cm

Applying mirror's formula,1/v +1/u = 1/f

1/v + 1/-10 = 1/-15

1/v = -1/15 + 1/10

=(-2+3)/30

= 1/30

V = 30 cm.

Hence, we get enlarged image, virtual in nature having magnification 3.

Explanation:

hope it helps..

Answered by Ekaro
4

Given :

Distance of object = 10cm

A real, enlarged image is formed at a distance of 5cm from the object.

(Hence distance of image from pole will be 15cm)

Type of mirror : concave

To Find :

Focal length of the mirror.

Solution :

❖ Focal length of concave mirror is taken negative and that of convex mirror is taken positive.

Focal length of mirror can be calculated by using mirror formula which is given by

\dag\:\underline{\boxed{\bf{\red{\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}}}}}

  • u denotes distance of object
  • v denotes distance of image
  • f denotes focal length

By substituting the given values;

\sf:\implies\:\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}

\sf:\implies\:\dfrac{1}{(-10)}+\dfrac{1}{(-15)}=\dfrac{1}{f}

\sf:\implies\:\dfrac{(-3-2)}{30}=\dfrac{1}{f}

\sf:\implies\:f=-\dfrac{30}{5}

:\implies\:\underline{\boxed{\bf{\purple{f=-6\:cm}}}}

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