Question

An object is placed at a distance of 10cm from a concave mirror of focal length 5cm. find the nature and position of image?
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Answer 1

Step-by-step explanation:

• Object Distance ,u = -10 cm
• Focal length ,f = -5 cm

To Find:-

• Nature & Position of Image

Solution:-

As we have to calculate the nature and position of Image. Using mirror formula

• • 1/v + 1/u = 1/f

where ,

• v is the Image Position
• u is the object distance
• f is the focal length

Substitute the value we get

→ 1/v = 1/f - 1/u

→ 1/v = 1/-5 - 1/-10

→ 1/v = -1/5 + 1/10

→ 1/v = -2+1/10

→ 1/v = -1/10

→ v = -10 cm

• Hence, the image position is on the Center of Curvature and the image distance is 10 cm left from the pole.

Now, calculating the magnification

• m = -v/u

substitute the value we get

→ m = -(-10)/-10

→ m = 10/-10

→ m = -10/10

→ m = -1

• Here , negative sign show that the image formed is real & inverted and as the same size as the object .

Answer 2

Step-by-step explanation:

Given,

IN CASE OF THE CONCAVE MIRROR

object distance (u) = -10cm (behind the mirror).

focal length (f) = -5cm (behind the mirror).

BY THR THE MIRROR FORMULA,,

1/u + 1/v = 1/f.

; (-1/10) + 1/v = (-1/5).

; 1/v = 1/10 - 1/5.

; 1/v = 1-2/10. ( by doing LCM the fraction).

; 1/v = (-1/10).

RECIPROCAL THE FRACTION,,

; v = -10cm.

; image distance (v) = -10cm.

As we know that,

m = -v/u.

= -(-10)/(-10).

= -1.

So, the magnification is negative then, the size of the image is same as the object & nature of the image is real and inverted.

Position of the image is real, inverted.

HOPE IT WILL BE HELPFUL