Question

An object is placed at a distance of 10cm from a convex mirror of focal length 15cm.Find the magnification.

Answer 1

Explanation:

$u = -10 \: cm \: , f =15 \: cm$

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\frac{1}{15} = \frac{1}{v} + \frac{1}{-10}$

$\frac{1}{15} = \frac{1}{v} + \frac{-1}{10}$

$\frac{1}{v} = \frac{1}{15} + \frac{1}{10}$

$\frac{1}{v} = \frac{2}{30} + \frac{3}{30}$

$\frac{1}{v} =\frac{5}{30}$

$v =\frac{30}{5}=6 \: cm$

$magnification(m)=\frac{-v}{u}$

$m =\frac{-6}{-10}$

$m = 0.6$