An object is placed at a distance of 10cm from a diverging lens of focal length 15cm. Find the position and nature of the image formed. Also, calculate the magnification of the image.
Answers
Answer: -0.6cm
Explanation: a DIVERGING LENS is a concave len. Therefore you use negative symbols Then use the lens formula
6cm.
Explanation:
object distance of 10cm
focal length 15cm.
mirror type = diverging
WKT;
1/f = 1/v + 1/u
therefore, 1/v = 1/f - 1/u
1/v = 1/15 _ (-1/10)
=> 1/15 + 1/10
=> 1/v = (2+3)/30
hence v = 30/5 = 6cm.
The nature of the image formed:
When the v is positive, the image is formed behind the mirror, and in front of the mirror when the v is negative.
Our resultant value indicates that the image is produced behind the mirror at a distance of 6cm from the pole of the mirror in this scenario.
When v is positive, the resulting image is virtual.
Hence, the image is formed behind the mirror and it is virtual.
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