Question

An object is placed at a distance of 10cm on the principal axis of the convex lens whose focal length of it observed at a distance of 30cm from lens find the nature and magnification of images​

Answer 1

The image distance is 7.5 cm and the height of the image is 0.75 cm.

Explanation:

Given that,

Focal length of the convex lens, f = 30 cm

Object distance, u = -10 cm

The lens formula is given by :

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\dfrac{1}{(30)}=\dfrac{1}{v}-\dfrac{1}{(-10)}$

v = 7.5 cm

On solving we get the value of image distance as (7.5 cm). The formula of the magnification of lens is given by :

$m=\dfrac{h'}{h}=\dfrac{-v}{u}$

$m=\dfrac{-7.5}{(-10)}$

h = 0.75 cm

So, the image distance is 7.5 cm and the height of the image is 0.75 cm. Hence, this is the required solution.

Learn more,

Lens formula

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Answer 2

Answer:

0.75

Explanation:

No explaining, since it's simple to do